Question 3. in Fig. 6.30, If Ab || Cd, Ef ? Cd and ? Ged = 126°, Exercise 6.2 Chapter 6 Lines and Angles Maths Class

Question 3. In Fig. 6.30, if AB || CD, EF ? CD and ? GED = 126°, find ? AGE, ? GEF and ? F Chapter 6: Lines and Angles Maths Class 9 solutions are developed for assisting understudies with working on their score and increase knowledge of the subjects. Question 3. In Fig. 6.30, if AB || CD, EF ⊥ CD and ∠ GED = 126°, find ∠ AGE, ∠ GEF and ∠ FGE. is solved by our expert teachers. You can get ncert solutions and notes for class 9 chapter 6 absolutely free. NCERT Solutions for class 9 Maths Chapter 6: Lines and Angles is very essencial for getting good marks in CBSE Board examinations

Question 3. In Fig. 6.30, if AB || CD, EF ⊥ CD and ∠ GED = 126°, find ∠ AGE, ∠ GEF and ∠ FGE.

Solution :
∠GEF + ∠FEG = ∠GED
EF ⊥ CD so that ∠ FED = 90°
And given that ∠ GED = 126°
Plug the values we get
∠GEF + 90° = 126°
∠GEF = 126°- 90°
∠GEF = 36°

AB || CD, EF ⊥ CD so ∠EFG = 90°
Use angle sum property of triangle (sum is 180°)
∠GEF + ∠EFG + ∠FGE = 180°
Plug the values we get
36° + 90° + ∠FGE = 180°
∠FGE = 180° – 36° - 90°
∠FGE = 54°

AB is a straight line so that use linear pair property
∠AGE +∠FGE = 180°
Plug the value of ∠FGE = 54°
We get
∠AGE +54° = 180°
∠AGE = 180° - 54°
∠AGE = 126°